If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3r^2+14r-24=0
a = 3; b = 14; c = -24;
Δ = b2-4ac
Δ = 142-4·3·(-24)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-22}{2*3}=\frac{-36}{6} =-6 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+22}{2*3}=\frac{8}{6} =1+1/3 $
| 4x+5=-15-x | | (2x)^2+(x-1)=13^2 | | 3x4-16x4=0 | | 3(5-x)-2(5+x)=3(×+1) | | 9((k-4)-7k=32-2(k+8) | | 6x^2-13x-7=2 | | 2/x=-5/6 | | 84=4(6+3x) | | 6(5+5x)=-240 | | 16−2t=2/3t+9 | | 3(6+5y)=2(–5+4y) | | 38+2x+25=x+163 | | 50-5d=4d+5 | | 9^2+6x+1=0 | | -69=3(1+6a) | | 6(10-7x)=-318 | | 2x(12x+9)=0 | | 14+12=-15x=2x | | 72=6x+3(4+2x) | | x+9/3=2x+2/4 | | 2x+x-7=0 | | 16z=32 | | 2(x-1)-3(2x-5)=-3 | | 14=12=-15x=2x | | -7(5x+9)=-133 | | 4(-5v=6)=-96 | | 3/8=30/x | | g-1+ -6= -8 | | 5x+7x-4=3(4x+3) | | 85=-5+5(3m+6) | | |4x+8|=24 | | 16=4(m+1) |